z^(-16/3)

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Solution for z^(-16/3) equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

z^(-16/3) = 0

1*z^(-16/3) = 0 // : 1

z^(-16/3) = 0

z należy do O

z belongs to the empty set

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